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Diseño
de Tanques de Almacenamiento Atmosférico por API Std 650
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Cálculo de espesores por el Método de punto de Diseño Variable
(5.6.4)
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Tablas y Estándares
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-
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API Std 650
Welded Tanks for oil Storage, para. 5.6.4
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-
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Espesor
Minimo de Placas por API Std 650 (5.6.1.1)
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-
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Espesor de
Placas por ASME / ASTM
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-
|
Tablas 5-2a
y 5-2b Esfuerzo permisible para condiciones de diseño y Prueba Hidrostatica
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METODO DE
PUNTO DE DISEÑO VARIABLE
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(Ingrese valores en celdas amarillas para cálculos)
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DATOS
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Capacidad (Barriles)
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ft³
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G (Gravedad Especifica del Fluido)
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Fluid
Density, r (Lb/ft³) (1)
|
|
Note (1):
|
(Consider r ≥ 62,43 Lb/ft³ for the Hmáx calculation)
|
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Ground
Resistance, Ps (Lb/in²)
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Outage (ft) (2)
|
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Nota (2):
|
(Distancia desde el nivel máximo hasta el borde
superior)
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Anillo
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Especificación
de Placas
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Ancho de
Placas, E (ft)
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Esfuerzo de
Prueba Hidrostática, St (psi)
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Esfuerzo de
Diseño, Sd (psi)
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Tolerancia
de Corrosión, CA (in.)
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Hmáx = 1728*Ps/ρ
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in. =
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ft
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Htanq ≤ Hmáx
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ft
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h = Htanq-outage
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ft
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D = (V 4/πh)⁰∙⁵
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ft =
|
|
ft³ =
|
|
barriles
|
De acuerdo a
API Std 650
|
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Dtanq
|
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ft =
|
|
ft³ =
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|
barriles
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No. de Anillos = Htanq/E
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RESULTADOS
tmin Y SELECCION tuse
|
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|
Anillos
|
Condición
de Diseño
(in.)
|
Condición
de Prueba Hidrostatica
(in.)
|
tmin
(in.)
|
tuse (*)
(in.)
|
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t1
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t2
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t3
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t4
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t5
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t6
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t7
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t8
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Notas:
|
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|
- Dimensiones en in.
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|
|
- (*) Verificar Espesor minimo de placas por API
Std 650 (5.6.1.1)
|
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|
CALCULO DEL
ESPESOR DEL 1ER ANILLO (N=1)
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N
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|
H = Htanq - (N-1)E
|
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|
ft
|
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|
CONDICIONES
DE DISEÑO
|
|
|
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|
|
tpd
=
|
2.6D(H-1)G
|
+ CA
|
|
|
|
|
|
|
|
|
in.
|
|
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|
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|
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|
Sd
|
|
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|
|
t1d
=
|
[
|
1.06 -
|
0.463D
|
(
|
HG
|
)
|
0,5
|
]
|
(
|
2.6HDG
|
)
|
+ CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
H
|
Sd
|
|
Sd
|
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|
t1d
no necesariamente debe ser mayor que tpd
|
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|
El menor entre tpd y t1d
|
|
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|
|
|
|
|
CONDICIONES
DE PRUEBA HIDROSTATICA
|
|
|
|
|
|
|
|
|
|
tpt =
|
2.6D(H-1)
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
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|
St
|
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|
|
t1t =
|
[
|
1.06 -
|
0.463D
|
(
|
H
|
)
|
0,5
|
]
|
(
|
2.6HD
|
)
|
|
|
in.
|
|
|
|
|
|
|
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|
|
|
H
|
St
|
|
St
|
|
|
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|
|
t1t
no necesariamente debe ser mayor que tpt
|
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|
El menor entre tpt y t1t
|
|
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|
|
|
|
|
|
|
ESPESOR DEL
PRIMER ANILLO
|
|
|
|
|
|
|
|
|
|
El mayor entre t1d y t1t
(t1min)
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
t1use
|
|
|
|
|
|
|
|
|
|
in.
|
t1use> t1min
|
|
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|
|
Verificar L/H ≤ 2
|
|
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|
t = t1use - CA
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
L = (6 D t)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
H = Htanq - (N-1)E
|
|
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|
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|
L/H =
|
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|
|
CALCULO DEL ESPESOR DEL 2DO ANILLO (N=2)
|
|
|
|
|
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|
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|
|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t2a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t1
= t1use - CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
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|
|
|
h1
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
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|
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|
|
R =
|
h1
|
|
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|
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|
|
|
|
|
|
(r t1)⁰∙⁵
|
|
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|
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|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
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|
|
|
Como R =
|
|
→
|
|
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|
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|
|
|
|
|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
|
|
h1
|
|
in.
|
h1
|
|
in.
|
h1
|
|
in.
|
h1
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
psi
|
Sd
|
|
psi
|
Sd
|
|
psi
|
Sd
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t1d = t1use
|
|
in.
|
t1d = t1use
|
|
in.
|
t1d = t1use
|
|
in.
|
t1d = t1use
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
2.6D(H-1)G
|
|
|
|
|
|
|
|
|
|
|
in.
|
tdx-CA
|
|
in.
|
tdx1-CA
|
|
in.
|
tdx2-CA
|
|
in.
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL = t1use - CA
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t1use-CA
|
|
in.
|
tL = t1use-CA
|
|
in.
|
tL = t1use-CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
in.
|
tu = tdx-CA
|
|
in.
|
tu = tdx1-CA
|
|
in.
|
tu = tdx2-CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 12CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tdx - CA=
|
2.6D(H-X/12)G
|
|
|
|
|
|
|
|
|
|
|
in.
|
tdx1-CA
|
|
in.
|
tdx2-CA
|
|
in.
|
tdx3-CA
|
|
in.
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA)
=
|
|
|
tu-(tdx2-CA)
=
|
|
|
tu-(tdx3-CA)
=
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t2a
= tdx-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t2d =
t2 + CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t2a
= ttx)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t₁ = t1use
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
h1
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h1
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t1)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Como R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h1
|
|
in.
|
h1
|
|
in.
|
h1
|
|
|
h1
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
psi
|
St
|
|
psi
|
St
|
|
|
St
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t1t
=
|
[
|
1.06 -
|
0.463D
|
(
|
H
|
)
|
0,5
|
]
|
(
|
2.6HD
|
)
|
|
|
in.
|
t1t
|
|
in.
|
t1t
|
|
|
t1t
|
|
in.
|
|
|
H
|
St
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpt =
|
2.6D(H-1)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx
|
|
in.
|
ttx1
|
|
|
ttx2
|
|
in.
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t1t
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t1t
|
|
in.
|
tL = t1t
|
|
|
tL = t1t
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
in.
|
tu = ttx
|
|
in.
|
tu = ttx₁
|
|
|
tu = ttx2
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 12CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ttx =
|
2.6D(H-X/12)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx1
|
|
in.
|
ttx2
|
|
|
ttx3
|
|
in.
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t₂ₐ
= ttx
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t₂t = t₂
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ESPESOR DEL SEGUNDO ANILLO
|
|
|
|
|
|
|
|
t2min
es el mayor valor entre t2d y t2t
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
t2use
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
(El espesor adicional no
será usado para calculos subsecuentes)
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CALCULO DEL ESPESOR DEL 3ER ANILLO (N=3)
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t3a = tdx-CA)
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CALCULAR LA RELACIÓN R
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t2
= t2min-CA
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in.
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h2
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ft
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in.
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r
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ft
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in.
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R =
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h2
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(r x t2)⁰∙⁵
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R ≤
1.375
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→
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R ≥
2.625
|
→
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1.375 < R < 2.625
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→
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Como R =
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→
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1ra Iteración
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2da Iteración
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3ra Iteración
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N (Anillo Inferior)
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N (Inf)
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N (Inf)
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N (Inf)
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N (Anillo en Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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Dtanq
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ft
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Dtanq
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ft
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Dtanq
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Dtanq
|
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ft
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h2
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in.
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h2
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in.
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h2
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h2
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in.
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r
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in.
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r
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in.
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r
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r
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in.
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E
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ft
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E
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ft
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E
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E
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ft
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Htanq
|
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ft
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Htanq
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ft
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Htanq
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Htanq
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ft
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H = Htanq - (N-1)*E (Inferior)
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ft
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H (Inf)
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ft
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H (Inf)
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H (Inf)
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ft
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H = Htanq - (N-1)*E (En Ánalisis)
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ft
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H (Ánalisis)
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ft
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H (Ánalisis)
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H (Ánalisis)
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ft
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G
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G
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G
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G
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Sd
|
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psi
|
Sd
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psi
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Sd
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Sd
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psi
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CA
|
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in.
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CA
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in.
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CA
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CA
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in.
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tpd - CA=
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2.6D(H-1)G
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in.
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tdx-CA
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in.
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tdx1-CA
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tdx2-CA
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in.
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Sd
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tL
= t2d-CA
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in.
|
tL = t2d-CA
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in.
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tL = t2d-CA
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tL = t2d-CA
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in.
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tu
= tpd-CA
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in.
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tu = tdx-CA
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in.
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tu = tdx1-CA
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tu = tdx2-CA
|
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in.
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
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X₁
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X₁
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X₂ = 12CH
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X₂
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X₂
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X₂
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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tdx - CA=
|
2.6D(H-X/12)G
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in.
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tdx1-CA
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in.
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tdx2-CA
|
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tdx3-CA
|
|
in.
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|
|
Sd
|
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Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
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tu-(tdx-CA) =
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tu-(tdx1-CA) =
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tu-(tdx2-CA) =
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tu-(tdx3-CA) =
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t3a
= tdx-CA
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in.
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in.
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t3d =
t3 + CA
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in.
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t3a
= ttx)
|
|
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|
|
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|
|
CALCULAR LA RELACIÓN R
|
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|
t2
= t2min
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in.
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|
h2
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ft
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in.
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|
r
|
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|
ft
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in.
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R =
|
h2
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|
|
|
|
|
|
(r x t2)⁰∙⁵
|
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R ≤
1.375
|
→
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R ≥
2.625
|
→
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|
1.375 < R < 2.625
|
→
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Como R =
|
|
→
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1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
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|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
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|
N (Inf)
|
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|
N (Anillo en Ánalisis)
|
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|
N (Ánalisis)
|
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|
N (Ánalisis)
|
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|
N (Ánalisis)
|
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|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h2
|
|
in.
|
h2
|
|
in.
|
h2
|
|
|
h2
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
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|
|
St
|
|
psi
|
St
|
|
psi
|
St
|
|
|
St
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
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|
t2t
= t2
|
|
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|
|
|
|
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|
|
in.
|
t2t = t2
|
|
in.
|
t2t = t2
|
|
|
t2t = t2
|
|
in.
|
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|
tpt =
|
2.6D(H-1)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx
|
|
in.
|
ttx1
|
|
|
ttx2
|
|
in.
|
|
|
St
|
|
|
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|
|
tL
= t2t
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t2t
|
|
in.
|
tL = t2t
|
|
|
tL = t2t
|
|
in.
|
|
|
|
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|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = ttx
|
|
in.
|
tu = ttx1
|
|
|
tu = ttx2
|
|
in.
|
|
|
|
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|
|
K = tL/tu
|
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|
K
|
|
|
K
|
|
|
K
|
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|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
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X₁
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X₁
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X₂ = 12CH
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X₂
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X₂
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X₂
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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ttx =
|
2.6D(H-X/12)
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in.
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ttx1
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in.
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ttx2
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ttx3
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in.
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St
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Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
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tu-ttx =
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tu-ttx1 =
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tu-ttx2 =
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tu-ttx3 =
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t3a = ttx
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in.
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in.
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t3t
= t3
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in.
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ESPESOR DEL TERCER ANILLO
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t3min
es el mayor valor entre t3d y t3t
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in.
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t3use
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in.
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CALCULO DEL ESPESOR DEL 4TO ANILLO (N=4)
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t4a = tdx-CA)
|
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CALCULAR LA RELACIÓN R
|
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t3
= t3min-CA
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in.
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h3
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ft
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in.
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r
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ft
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in.
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R =
|
h3
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(r x t3)⁰∙⁵
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R ≤
1.375
|
→
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R ≥
2.625
|
→
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1.375 < R < 2.625
|
→
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Como R =
|
|
→
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1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
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|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
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|
N (Ánalisis)
|
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|
N (Ánalisis)
|
|
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|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h3
|
|
in.
|
h3
|
|
in.
|
h3
|
|
|
h3
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
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|
|
Sd
|
|
psi
|
Sd
|
|
psi
|
Sd
|
|
|
Sd
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
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|
tpd - CA=
|
2.6D(H-1)G
|
|
|
|
|
|
|
|
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|
|
in.
|
tdx-CA
|
|
in.
|
tdx1-CA
|
|
|
tdx2-CA
|
|
in.
|
|
|
Sd
|
|
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|
|
tL
= t3d-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t3d-CA
|
|
in.
|
tL = t3d-CA
|
|
|
tL = t3d-CA
|
|
in.
|
|
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|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = tdx-CA
|
|
in.
|
tu = tdx1-CA
|
|
|
tu = tdx2-CA
|
|
in.
|
|
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|
|
K = tL/tu
|
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|
K
|
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|
K
|
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|
K
|
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|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
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|
C
|
|
|
C
|
|
|
C
|
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|
|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 12CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
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|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
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|
|
tdx - CA=
|
2.6D(H-X/12)G
|
|
|
|
|
|
|
|
|
|
|
in.
|
tdx1-CA
|
|
in.
|
tdx2-CA
|
|
|
tdx3-CA
|
|
in.
|
|
|
Sd
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
|
|
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|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
|
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|
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|
|
|
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|
|
t4a
= tdx-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
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|
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|
in.
|
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|
|
t4d
= t4 + CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
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|
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|
|
|
|
|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t4a
= ttx)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t3
= t3min
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
h3
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h3
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t3)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
Como R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
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|
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|
|
|
|
|
|
|
|
|
|
|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h3
|
|
in.
|
h3
|
|
in.
|
h3
|
|
|
h3
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
psi
|
St
|
|
psi
|
St
|
|
|
St
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
|
|
|
|
|
|
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|
|
t3t
= t3
|
|
|
|
|
|
|
|
|
|
|
in.
|
t3t = t3
|
|
in.
|
t3t = t3
|
|
|
t3t = t3
|
|
in.
|
|
|
|
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|
|
tpt =
|
2.6D(H-1)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx
|
|
in.
|
ttx1
|
|
|
ttx2
|
|
in.
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
tL
= t3t
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t3t
|
|
in.
|
tL = t3t
|
|
|
tL = t3t
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
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|
|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = ttx
|
|
in.
|
tu = ttx1
|
|
|
tu = ttx2
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 12CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ttx =
|
2.6D(H-X/12)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx1
|
|
in.
|
ttx2
|
|
|
ttx3
|
|
in.
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t4a
= ttx
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t4t
= t4
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
ESPESOR DEL CUARTO ANILLO
|
|
|
|
|
|
|
|
t4min
es el mayor valor entre t4d y t4t
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
t4use
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
CALCULO DEL ESPESOR DEL 5TO ANILLO (N=5)
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t5a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t4
= t4min-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
h4
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R =
|
h4
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t4)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Como R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h4
|
|
in.
|
h4
|
|
in.
|
h4
|
|
|
h4
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
psi
|
Sd
|
|
psi
|
Sd
|
|
|
Sd
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
2.6D(H-1)G
|
|
|
|
|
|
|
|
|
|
|
in.
|
tdx-CA
|
|
in.
|
tdx1-CA
|
|
|
tdx2-CA
|
|
in.
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t4d-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t4d-CA
|
|
in.
|
tL = t4d-CA
|
|
|
tL = t4d-CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = tdx-CA
|
|
in.
|
tu = tdx1-CA
|
|
|
tu = tdx2-CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 12CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tdx - CA=
|
2.6D(H-X/12)G
|
|
|
|
|
|
|
|
|
|
|
in.
|
tdx1-CA
|
|
in.
|
tdx2-CA
|
|
|
tdx3-CA
|
|
in.
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
tu-(tdx1-CA) =
|
|
|
tu-(tdx2-CA) =
|
|
|
tu-(tdx3-CA) =
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t5a
= tdx-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t5d
= t5 + CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t5a
= ttx)
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CALCULAR LA RELACIÓN R
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t4
= t4min
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in.
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h4
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ft
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in.
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r
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ft
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in.
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R =
|
h4
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(r x t4)⁰∙⁵
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R ≤
1.375
|
→
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R ≥
2.625
|
→
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1.375 < R < 2.625
|
→
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Como R =
|
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→
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1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
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N (Anillo Inferior)
|
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|
N (Inf)
|
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N (Inf)
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N (Inf)
|
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N (Anillo en Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
|
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Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
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|
h4
|
|
in.
|
h4
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in.
|
h4
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h4
|
|
in.
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|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
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E
|
|
ft
|
E
|
|
ft
|
E
|
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E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
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|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
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|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
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|
H (Ánalisis)
|
|
ft
|
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G
|
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G
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G
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G
|
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St
|
|
psi
|
St
|
|
psi
|
St
|
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|
St
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
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CA
|
|
in.
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t4t
= t4
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in.
|
t4t = t4
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in.
|
t4t = t4
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|
t4t = t4
|
|
in.
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tpt =
|
2.6D(H-1)
|
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|
|
in.
|
ttx
|
|
in.
|
ttx1
|
|
|
ttx2
|
|
in.
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|
|
St
|
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tL
= t4t
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|
in.
|
tL = t4t
|
|
in.
|
tL = t4t
|
|
|
tL = t4t
|
|
in.
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tu
= tpt
|
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|
|
in.
|
tu = ttx
|
|
in.
|
tu = ttx1
|
|
|
tu = ttx2
|
|
in.
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K = tL/tu
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K
|
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K
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K
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|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
|
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C
|
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C
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|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
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|
|
X₂ = 12CH
|
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|
X₂
|
|
|
X₂
|
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|
X₂
|
|
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|
|
X₃ = 1.22(rtu)⁰∙⁵
|
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|
X₃
|
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|
X₃
|
|
|
X₃
|
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|
X
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|
X
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|
X
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|
X
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|
ttx =
|
2.6D(H-X/12)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx1
|
|
in.
|
ttx2
|
|
|
ttx3
|
|
in.
|
|
|
St
|
|
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|
|
|
Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
|
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tu-ttx =
|
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|
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|
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|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
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|
tu-ttx3 =
|
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|
t5a
= ttx
|
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|
|
|
|
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|
in.
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in.
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|
t5t
= t5
|
|
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|
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|
in.
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|
ESPESOR DEL QUINTO ANILLO
|
|
|
|
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|
|
|
t5min
es el mayor valor entre t5d y t5t
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
t5use
|
|
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|
in.
|
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|
|
CALCULO DEL ESPESOR DEL 6TO ANILLO (N=6)
|
|
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|
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|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t6a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t5
= t5min-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
h5
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
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|
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|
R =
|
h5
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t5)⁰∙⁵
|
|
|
|
|
|
|
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|
|
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|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
Como R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h5
|
|
in.
|
h5
|
|
in.
|
h5
|
|
|
h5
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
Sd
|
|
psi
|
Sd
|
|
psi
|
Sd
|
|
|
Sd
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpd - CA=
|
2.6D(H-1)G
|
|
|
|
|
|
|
|
|
|
|
in.
|
tdx-CA
|
|
in.
|
tdx1-CA
|
|
|
tdx2-CA
|
|
in.
|
|
|
Sd
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t5d-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t5d-CA
|
|
in.
|
tL = t5d-CA
|
|
|
tL = t5d-CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpd-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = tdx-CA
|
|
in.
|
tu = tdx1-CA
|
|
|
tu = tdx2-CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
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|
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
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X₁
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X₁
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X₂ = 12CH
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X₂
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X₂
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X₂
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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tdx - CA=
|
2.6D(H-X/12)G
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in.
|
tdx1-CA
|
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in.
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tdx2-CA
|
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tdx3-CA
|
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in.
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Sd
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Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
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tu-(tdx-CA) =
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tu-(tdx1-CA) =
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tu-(tdx2-CA) =
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tu-(tdx3-CA) =
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t6a
= tdx-CA
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in.
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in.
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t6d
= t6 + CA
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in.
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t6a
= ttx)
|
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CALCULAR LA RELACIÓN R
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t5
= t5min
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in.
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h5
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ft
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in.
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r
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ft
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in.
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R =
|
h5
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(r x t5)⁰∙⁵
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R ≤
1.375
|
→
|
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R ≥
2.625
|
→
|
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1.375 < R < 2.625
|
→
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Como R =
|
|
→
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|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h5
|
|
in.
|
h5
|
|
in.
|
h5
|
|
|
h5
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
psi
|
St
|
|
psi
|
St
|
|
|
St
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
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|
t5t
= t5
|
|
|
|
|
|
|
|
|
|
|
in.
|
t5t = t5
|
|
in.
|
t5t = t5
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|
|
t5t = t5
|
|
in.
|
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|
|
tpt =
|
2.6D(H-1)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx
|
|
in.
|
ttx1
|
|
|
ttx2
|
|
in.
|
|
|
St
|
|
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|
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|
|
tL
= t5t
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t5t
|
|
in.
|
tL = t5t
|
|
|
tL = t5t
|
|
in.
|
|
|
|
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|
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|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = ttx
|
|
in.
|
tu = ttx1
|
|
|
tu = ttx2
|
|
in.
|
|
|
|
|
|
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|
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|
|
K = tL/tu
|
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|
K
|
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|
K
|
|
|
K
|
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|
|
C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
|
|
|
|
|
|
|
|
|
|
|
C
|
|
|
C
|
|
|
C
|
|
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|
|
|
|
|
X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
|
|
|
|
|
|
|
|
|
|
|
|
X₁
|
|
|
X₁
|
|
|
X₁
|
|
|
|
|
X₂ = 12CH
|
|
|
|
|
|
|
|
|
|
|
X₂
|
|
|
X₂
|
|
|
X₂
|
|
|
|
|
X₃ = 1.22(rtu)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
X₃
|
|
|
X₃
|
|
|
X₃
|
|
|
|
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|
|
|
|
|
X
|
|
|
|
|
|
|
|
|
|
|
X
|
|
|
X
|
|
|
X
|
|
|
|
|
|
|
|
|
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|
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|
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|
|
|
|
|
|
ttx =
|
2.6D(H-X/12)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx1
|
|
in.
|
ttx2
|
|
|
ttx3
|
|
in.
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
|
|
|
|
|
|
|
|
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|
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|
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|
|
|
tu-ttx =
|
|
|
|
|
|
|
|
|
|
|
|
tu-ttx1 =
|
|
|
tu-ttx2 =
|
|
|
tu-ttx3 =
|
|
|
|
|
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|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
t6a
= ttx
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
|
|
in.
|
|
|
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|
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|
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|
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|
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|
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|
|
|
|
|
|
|
|
|
|
|
t6t
= t6
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
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|
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|
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|
|
|
|
|
|
|
|
ESPESOR DEL SEXTO ANILLO
|
|
|
|
|
|
|
|
t6min
es el mayor valor entre t6d y t6t
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
t6use
|
|
|
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
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|
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|
|
|
|
|
|
|
|
CALCULO DEL ESPESOR DEL 7MO ANILLO (N=7)
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t7a = tdx-CA)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t6
= t6min-CA
|
|
|
|
|
|
|
|
|
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
h6
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
|
r
|
|
|
|
|
|
|
|
|
|
|
ft
|
|
in.
|
|
|
|
|
|
|
|
|
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|
|
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|
|
|
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|
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|
|
|
|
|
|
|
R =
|
h6
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
(r x t6)⁰∙⁵
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≤
1.375
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
1.375 < R < 2.625
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Como R =
|
|
→
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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1ra Iteración
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2da Iteración
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3ra Iteración
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N (Anillo Inferior)
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N (Inf)
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N (Inf)
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N (Inf)
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N (Anillo en Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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Dtanq
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ft
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Dtanq
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ft
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Dtanq
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Dtanq
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ft
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h6
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in.
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h6
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in.
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h6
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h6
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in.
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r
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in.
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r
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in.
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r
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r
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in.
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E
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ft
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E
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ft
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E
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E
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ft
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Htanq
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ft
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Htanq
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ft
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Htanq
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Htanq
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ft
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H = Htanq - (N-1)*E (Inferior)
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ft
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H (Inf)
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ft
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H (Inf)
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H (Inf)
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ft
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H = Htanq - (N-1)*E (En Ánalisis)
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ft
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H (Ánalisis)
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ft
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H (Ánalisis)
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H (Ánalisis)
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ft
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G
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G
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G
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G
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Sd
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psi
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Sd
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psi
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Sd
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Sd
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psi
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CA
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in.
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CA
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in.
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CA
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CA
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in.
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tpd - CA=
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2.6D(H-1)G
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in.
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tdx-CA
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in.
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tdx1-CA
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tdx2-CA
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in.
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Sd
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tL
= t6d-CA
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in.
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tL = t6d-CA
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in.
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tL = t6d-CA
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tL = t6d-CA
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in.
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tu
= tpd-CA
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in.
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tu = tdx-CA
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in.
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tu = tdx1-CA
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tu = tdx2-CA
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in.
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
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X₁
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X₁
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X₂ = 12CH
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X₂
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X₂
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X₂
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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tdx - CA=
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2.6D(H-X/12)G
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in.
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tdx1-CA
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in.
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tdx2-CA
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tdx3-CA
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in.
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Sd
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Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
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tu-(tdx-CA) =
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tu-(tdx1-CA) =
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tu-(tdx2-CA) =
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tu-(tdx3-CA) =
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t7a
= tdx-CA
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in.
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in.
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t7d
= t7 + CA
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in.
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t7a
= ttx)
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CALCULAR LA RELACIÓN R
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t6
= t6min
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in.
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h6
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ft
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in.
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r
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ft
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in.
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R =
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h6
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(r x t6)⁰∙⁵
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R ≤
1.375
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→
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R ≥
2.625
|
→
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1.375 < R < 2.625
|
→
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Como R =
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→
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1ra Iteración
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2da Iteración
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3ra Iteración
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N (Anillo Inferior)
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N (Inf)
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N (Inf)
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N (Inf)
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N (Anillo en Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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Dtanq
|
|
ft
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Dtanq
|
|
ft
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Dtanq
|
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Dtanq
|
|
ft
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h6
|
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in.
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h6
|
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in.
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h6
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h6
|
|
in.
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r
|
|
in.
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r
|
|
in.
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r
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r
|
|
in.
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E
|
|
ft
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E
|
|
ft
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E
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E
|
|
ft
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Htanq
|
|
ft
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Htanq
|
|
ft
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Htanq
|
|
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Htanq
|
|
ft
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|
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H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
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H (Inf)
|
|
|
H (Inf)
|
|
ft
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|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
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H (Ánalisis)
|
|
ft
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H (Ánalisis)
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H (Ánalisis)
|
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ft
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G
|
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G
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G
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G
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St
|
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psi
|
St
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psi
|
St
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St
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|
psi
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CA
|
|
in.
|
CA
|
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in.
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CA
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CA
|
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in.
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t6t
= t6
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in.
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t6t = t6
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in.
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t6t = t6
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t6t = t6
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in.
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tpt =
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2.6D(H-1)
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in.
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ttx
|
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in.
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ttx1
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ttx2
|
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in.
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St
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tL
= t6t
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in.
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tL = t6t
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in.
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tL = t6t
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tL = t6t
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in.
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tu
= tpt
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in.
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tu = ttx
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in.
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tu = ttx1
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tu = ttx2
|
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in.
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
|
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X₁
|
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X₁
|
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X₂ = 12CH
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X₂
|
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X₂
|
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X₂
|
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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ttx =
|
2.6D(H-X/12)
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in.
|
ttx1
|
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in.
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ttx2
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ttx3
|
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in.
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St
|
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Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
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tu-ttx =
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tu-ttx1 =
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tu-ttx2 =
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tu-ttx3 =
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t7a
= ttx
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in.
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in.
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t7t
= t7
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in.
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ESPESOR DEL SEPTIMO ANILLO
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t7min
es el mayor valor entre t7d y t7t
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in.
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t7use
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in.
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CALCULO DEL ESPESOR DEL 8VO ANILLO (N=8)
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METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE DISEÑO (t8a = tdx-CA)
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CALCULAR LA RELACIÓN R
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t7
= t7min-CA
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in.
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h7
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ft
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in.
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r
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ft
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in.
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R =
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h7
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(r x t7)⁰∙⁵
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R ≤
1.375
|
→
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R ≥
2.625
|
→
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1.375 < R < 2.625
|
→
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Como R =
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→
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1ra Iteración
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2da Iteración
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3ra Iteración
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N (Anillo Inferior)
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N (Inf)
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N (Inf)
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N (Inf)
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N (Anillo en Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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N (Ánalisis)
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Dtanq
|
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ft
|
Dtanq
|
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ft
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Dtanq
|
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Dtanq
|
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ft
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h7
|
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in.
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h7
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in.
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h7
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h7
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in.
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r
|
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in.
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r
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in.
|
r
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r
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in.
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E
|
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ft
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E
|
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ft
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E
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E
|
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ft
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Htanq
|
|
ft
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Htanq
|
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ft
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Htanq
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Htanq
|
|
ft
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H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
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H (Inf)
|
|
ft
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H = Htanq - (N-1)*E (En Ánalisis)
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|
ft
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H (Ánalisis)
|
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ft
|
H (Ánalisis)
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H (Ánalisis)
|
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ft
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G
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G
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G
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G
|
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Sd
|
|
psi
|
Sd
|
|
psi
|
Sd
|
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|
Sd
|
|
psi
|
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CA
|
|
in.
|
CA
|
|
in.
|
CA
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CA
|
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in.
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tpd - CA=
|
2.6D(H-1)G
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in.
|
tdx-CA
|
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in.
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tdx1-CA
|
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tdx2-CA
|
|
in.
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|
Sd
|
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tL
= t7d-CA
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|
in.
|
tL = t7d-CA
|
|
in.
|
tL = t7d-CA
|
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|
tL = t7d-CA
|
|
in.
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tu
= tpd-CA
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in.
|
tu = tdx-CA
|
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in.
|
tu = tdx1-CA
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|
tu = tdx2-CA
|
|
in.
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K = tL/tu
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K
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K
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K
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
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X₁
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X₁
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X₂ = 12CH
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X₂
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X₂
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X₂
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|
X₃ = 1.22(rtu)⁰∙⁵
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X₃
|
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X₃
|
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|
X₃
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X
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X
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X
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X
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tdx - CA=
|
2.6D(H-X/12)G
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|
|
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|
|
|
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|
|
in.
|
tdx1-CA
|
|
in.
|
tdx2-CA
|
|
|
tdx3-CA
|
|
in.
|
|
|
Sd
|
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|
Verificar tu-(tdx-CA). Repetir usando el valor
calculado de tdx-CA hasta que
haya poca diferencia entre los valores calculados de tu y tdx-CA
|
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tu-(tdx-CA) =
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|
tu-(tdx1-CA) =
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|
tu-(tdx2-CA) =
|
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|
tu-(tdx3-CA) =
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|
t8a
= tdx-CA
|
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in.
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in.
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|
t8d
= t8 + CA
|
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|
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|
in.
|
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|
|
METODO DE LOS ANILLOS SUPERIORES PARA CONDICIONES
DE PRUEBA HIDROSTATICA (t8a
= ttx)
|
|
|
|
|
|
|
|
CALCULAR LA RELACIÓN R
|
|
|
|
|
|
|
|
t7
= t7min
|
|
|
|
|
|
|
|
|
|
|
in.
|
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|
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|
h7
|
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|
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|
|
|
|
|
|
ft
|
|
in.
|
|
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|
|
|
|
|
|
r
|
|
|
|
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|
|
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|
|
ft
|
|
in.
|
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|
R =
|
h7
|
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|
|
|
|
|
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|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
(r x t7)⁰∙⁵
|
|
|
|
|
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|
R ≤
1.375
|
→
|
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|
|
|
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|
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|
|
|
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|
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|
R ≥
2.625
|
→
|
|
|
|
|
|
|
|
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|
|
|
|
|
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|
|
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|
1.375 < R < 2.625
|
→
|
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|
|
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|
Como R =
|
|
→
|
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|
1ra Iteración
|
|
2da Iteración
|
|
3ra Iteración
|
|
|
|
N (Anillo Inferior)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
N (Inf)
|
|
|
|
|
N (Anillo en Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
N (Ánalisis)
|
|
|
|
|
Dtanq
|
|
ft
|
Dtanq
|
|
ft
|
Dtanq
|
|
|
Dtanq
|
|
ft
|
|
|
h7
|
|
in.
|
h7
|
|
in.
|
h7
|
|
|
h7
|
|
in.
|
|
|
r
|
|
in.
|
r
|
|
in.
|
r
|
|
|
r
|
|
in.
|
|
|
E
|
|
ft
|
E
|
|
ft
|
E
|
|
|
E
|
|
ft
|
|
|
Htanq
|
|
ft
|
Htanq
|
|
ft
|
Htanq
|
|
|
Htanq
|
|
ft
|
|
|
H = Htanq - (N-1)*E (Inferior)
|
|
ft
|
H (Inf)
|
|
ft
|
H (Inf)
|
|
|
H (Inf)
|
|
ft
|
|
|
H = Htanq - (N-1)*E (En Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
ft
|
H (Ánalisis)
|
|
|
H (Ánalisis)
|
|
ft
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
G
|
|
|
|
|
St
|
|
psi
|
St
|
|
psi
|
St
|
|
|
St
|
|
psi
|
|
|
CA
|
|
in.
|
CA
|
|
in.
|
CA
|
|
|
CA
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
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|
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|
|
|
|
|
|
t7t
= t7
|
|
|
|
|
|
|
|
|
|
|
in.
|
t7t = t7
|
|
in.
|
t7t = t7
|
|
|
t7t = t7
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tpt =
|
2.6D(H-1)
|
|
|
|
|
|
|
|
|
|
|
in.
|
ttx
|
|
in.
|
ttx1
|
|
|
ttx2
|
|
in.
|
|
|
St
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tL
= t7t
|
|
|
|
|
|
|
|
|
|
|
in.
|
tL = t7t
|
|
in.
|
tL = t7t
|
|
|
tL = t7t
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
tu
= tpt
|
|
|
|
|
|
|
|
|
|
|
in.
|
tu = ttx
|
|
in.
|
tu = ttx1
|
|
|
tu = ttx2
|
|
in.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
K = tL/tu
|
|
|
|
|
|
|
|
|
|
|
|
K
|
|
|
K
|
|
|
K
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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C = [K⁰∙⁵(K-1)]/(1-K¹∙⁵)
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C
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C
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C
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X₁ =
0.61(rtu)⁰∙⁵+(3.84CH)
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X₁
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X₁
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X₁
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X₂ = 12CH
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X₂
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X₂
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X₂
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X₃ = 1.22(rtu)⁰∙⁵
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X₃
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X₃
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X₃
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X
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X
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X
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X
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ttx =
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2.6D(H-X/12)
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in.
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ttx1
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in.
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ttx2
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ttx3
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in.
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St
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Verificar tu-ttx.
Repetir usando el valor calculado de ttx hasta que haya poca diferencia entre los valores calculados de
tu y ttx
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tu-ttx =
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tu-ttx1 =
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tu-ttx2 =
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tu-ttx3 =
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t8a
= ttx
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in.
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in.
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t8t
= t8
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in.
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ESPESOR DEL OCTAVO ANILLO
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t8min
es el mayor valor entre t8d y t8t
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in.
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t8use
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in.
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